Is it possible to estimate the octane increase of running 50/50 water methanol injection like below (idea by @CNM135i)?
I did one log with WMI before going back to 100% water and reducing nozzle size to 225cc (thanks to @F87Source)
Here are the results:
RON 98 WI 20C amb 6200rpm: -6% stft
RON 95 WI 14C amb 6200rpm: -5.5% stft
RON 95 WMI 20C amb 6200rpm: -12.5 stft
375cc nozzle
WMI = 50/50 water meth
WI = 100 water
16psi / 7deg timing / 11.4 afr @6200rpm
If methanol is 115 octane, and RON95 is 91 octane, would this mean that with WMI the effective average octane is
12.5 - 6 = 6.5% stft difference
115 - 91 = 24 octane difference
6.5% x 24 = 1.5 octane increase
Resulting in 91 + 1.5 = 92.5 octane
I did one log with WMI before going back to 100% water and reducing nozzle size to 225cc (thanks to @F87Source)
Here are the results:
RON 98 WI 20C amb 6200rpm: -6% stft
RON 95 WI 14C amb 6200rpm: -5.5% stft
RON 95 WMI 20C amb 6200rpm: -12.5 stft
375cc nozzle
WMI = 50/50 water meth
WI = 100 water
16psi / 7deg timing / 11.4 afr @6200rpm
If methanol is 115 octane, and RON95 is 91 octane, would this mean that with WMI the effective average octane is
12.5 - 6 = 6.5% stft difference
115 - 91 = 24 octane difference
6.5% x 24 = 1.5 octane increase
Resulting in 91 + 1.5 = 92.5 octane